wilddbill Posted April 2, 2015 Posted April 2, 2015 Goal:Identify users as they enter the home.Door lock is Yale Real LivingCode is as shown: This issue I’m having is no matter what code is entered the light turns on like it is ignoring the “if” statement.. WB
ILoveC4 Posted April 3, 2015 Posted April 3, 2015 I use that same programming and it works flawlessly. I'd verify you don't have other programming that is firing the light... perhaps when the door opens?
wilddbill Posted April 3, 2015 Author Posted April 3, 2015 nope.. the only thing that turns the light on is when the door is unlocked by code... can you show a clip of your code? does it look like mine? who could I turn to for support? WB
ILoveC4 Posted April 3, 2015 Posted April 3, 2015 If I get a chance later today I can it up and screenshot it for you. It looks just like yours though.
R_Willis Posted April 3, 2015 Posted April 3, 2015 Here is how mine looks.I fire off an email/txt to phones with what user opens the door lock according to their code.You could change the event after the first line to have it do whatever you want.
wilddbill Posted April 3, 2015 Author Posted April 3, 2015 Here is how mine looks.I fire off an email/txt to phones with what user opens the door lock according to their code.You could change the event after the first line to have it do whatever you want.there is something slightly different about your code which "Action did you use"?
cybuch Posted April 5, 2015 Posted April 5, 2015 Looks like he is programming off the username, not the user code, which is better. You might change the user code but not the username. His programing looks exactly the way mine does. Keep in mind the username is case sensitive,
wilddbill Posted April 6, 2015 Author Posted April 6, 2015 OK i set it up by user name as shown.. still no matter who enters the light comes on... can someone else try to this same code and see what they get? WB
turls Posted April 6, 2015 Posted April 6, 2015 ok.. I got it.. thanks for the help! So what was it? Looks like he is programming off the username, not the user code, which is better. You might change the user code but not the username. His programing looks exactly the way mine does. Keep in mind the username is case sensitive, And to be clear: as the username, this is the username as typed into the Yale app on the touchscreen (if I understand correctly and this is the way my system seems to work). How does this work with the new generic app that the new Touchscreens have (no flash Yale app on new touchscreens). Does it still work with usernames the same way?
luvness Posted August 31, 2015 Posted August 31, 2015 I am having trouble with this as well. I get an alert for each user if anyone opens the lock. For the life of me I can't seem to get the action "green arrow" indented below the programming "purple question mark". Once a user unlocks the door I get 12 text messages, one for each user. can someone tell me the steps to do this??
turls Posted September 1, 2015 Posted September 1, 2015 I am having trouble with this as well. I get an alert for each user if anyone opens the lock. For the life of me I can't seem to get the action "green arrow" indented below the programming "purple question mark". Once a user unlocks the door I get 12 text messages, one for each user. can someone tell me the steps to do this?? Well, it isn't going to work unless you figure that out. Just move the mouse around on top of the line with the question mark (if) statement, its a little to the right of the beginning of the line. Once you get it once it will be much easier going forward.
South Africa C4 user Posted September 1, 2015 Posted September 1, 2015 As Turls says you have to get the action indented below the if statement. When your mouse is in the right position to drop an indented action, the cursor will change to a right arrow. The rest of the time it will be an up arrow (meaning insert the code above the current line) or a down arrow (meaning insert the code - unindented - below the current line). The right arrow means indent the code under the if statement.
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